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A single core lead covered cable is to be designed for 132 kV to earth. Its conductor radius is 20 mm and its insulating material A, B and C have relative per mittivities 5, 4 and 3 respectively and corresponding maximum permissible stresses of 3.6, 2.4 and 2.0 kV/mm (rms) respectively. The minimum diameter of the lead steath will be _______ mm
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- 173.78 mm
- 1738 mm
- 1.7378 mm
- 173.8 mm
Correct Option: A
gmaxA = | ||
2πε0εAr |
gmax B = | ||
2πε0εBr1 |
gmax C = | ||
2πε0εCr2 |
εAr gmaxA = εBr1gmax B = εCr2gmax C
or 5 × 20 × 3.6 = 4 × r1 × 2.4 = 3 × r2 × 2.0
∴ r1 = | = 37.5 mm | |
4 × 2.4 |
and r2 = | = 60 mm | |
3 × 2.0 |
V1 gmax A r In | ![]() | ![]() | ||
r |
= 3.6 × 20 × In | ![]() | ![]() | = 45.25 kV | |
20 |
V2 gmax B r1 In | ![]() | ![]() | ||
r1 |
= 2.4 × 37.5 × In | ![]() | ![]() | = 42.3 kV | |
37.5 |
V3 gmax C r2 In | ![]() | ![]() | ||
r2 |
= 2.0 × 60 × In | ![]() | ![]() | ||
60 |
Now, 132 = 45.25 + 42.30 + 120 ln | ![]() | ![]() | ||
60 |
⇒ 44.45 = 120 ln | ![]() | ![]() | ||
60 |
⇒ 0.370 = ln | ![]() | ![]() | ||
60 |
⇒ = 86.89 mm
∴ Diameter of sheath = 2R = 2 × 86.89
= 173.78 mm