-
A 3-bus power system network consists of 3 transmission lines. The bus admittance matrix of the uncompensated system is
-j6 j3 j4 pu. j3 -j7 j5 -j4 j -j8
If the shunt capacitance of all transmission line is 50% compensated, the imaginary part of the 3rd row 3rd column element (in pu) of the bus admittance matrix after compensation is
-
- – j 7.0
- – j 8.5
- – j 7.5
- – j 9.0
Correct Option: B
yBus = | ![]() | y10 + y12 + y13 | -y12 | -y13 | ![]() | ||
-y12 | y20 + y21 + y23 | -y23 | |||||
-y13 | - y23 | y30 + y31 + y32 |
Now comparing with the given matrix, we get and
y31 = y13 = – j4
y32 = y23 = – j5
thus, y30 + y31 + y32
∴ y30 + (-j4) + (-j5) = -j8
∴ y30 = j1
Now, after compensating, y30 = j1/2
∴ y30 + y31 + y32 = j0.5 – j4 – j5 = – j8.5
∴ Option (b) is correct.