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Consider a three-core, three-phase, 50 H z, 11 kV cable whose conductors are denoted as R, Y and B in the figure given below. The inter-phase capacitance (C1) between each pair of conductors is 0.2 μF and the capacitance between each line conductor and the sheath is 0.4 μF. The per-phase charging current is Outer Sheath
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- 2.0 A
- 2.4 A
- 2.7 A
- 3.5 A
Correct Option: A
C1 = 0.2μF
C2 = 0.4 μF
Capacitance per phase,
C = 3C1 + C2 = 3 × 0.2 + 0.4 = 1 μF
ω = 2μf = 314 
∴ Charging current,
| Ic = | v.(ωC) | |
| xc |
| = | × 314 × 1 × 10-6 | |
| √3 |
= 2 amp
