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A 3-phase transmission line is shown in the figure. Voltage drop across the transmission line is given by the following equation:
Shunt capacitance of the line can be neglected. If the line has positive sequence impedance of 15 Ω and zero sequence impedance of 48 Ω, then the values of Zs and Zm will be
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- Zs = 31.5 Ω; Zm = 16.5 Ω
- Zs = 26 Ω; Zm = 11Ω
- Zs = 16.5 Ω; Zm = 31.5 Ω
- Zs = 11 Ω; Zm = 26 Ω
Correct Option: B
For the given system, the relationship between sequence impedance and Zs, Zm is given by Positive sequence impedance,
Z1 = Zs – Zm .
Negative sequence impedance,
Z2 = Zs – Zm .
Zero sequence impedance,
Z0 = Zs – 2Zm .
Given Zs – Zm = 15
and Zs + 2Zm = 48
Solving, we get,
Zs = 26, Zm = 11
