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On a section of a highway the speed-density relationship is linear and is
given by v = 80 - 2 k ; 3
where v is in km/h and k is the veh/kem. The capacity (in veh/h) of this section of the highway would be
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- 1200
- 2400
- 4800
- 9600
- 1200
Correct Option: B
Given , V = 80 - | k | |
3 |
Capacity of section, q = V × k
= | 80 - | k | × k = 80k - | k2 .......(1) | ||||
3 | 3 |
For maximum q,
Differentiate q. wrt k
= 0 | ||
dk |
⇒ 80 - | k = 0 | |
3 |
⇒ k = 60
Substitute in (1)
q = 80 × 60 - | × 602 = 2400 veh / hr | |
3 |