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It was observed that 150 vehicles crossed a particular location of a highway in a duration of 30 minutes. Assuming that vehicle arrival follows a negative exponential distribution, find out the number of time headways greater than 5 seconds in the above observation ?
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- 8.88
- 98.88
- 9
- None of the above
Correct Option: B
Probability of time head way greater than ‘tsec’ is given by p(h ≥ t) = e–m
If v = hourly flow rate, then
| m = | t | |
| 3600 |
| p(h ≥ t) = e–vt / 3600 = | = 0.659254 | ||
| e | 3600 |
No. of time headway greater than ‘t’ sec = (no of observed time headway) × p (h ≥ t)
= 150 × 0.65924 = 98.88
