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In the figure given below, lengths PQ(WCB : 30°) and QR (WCB : 45°) respectively up to three places of decimal are
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- 273.205, 938.186
- 273.205, 551.815
- 551.815, 551.815
- 551.815, 938.186
- 273.205, 938.186
Correct Option: A
Let PQ = a, QR = b
Line PQ
Latitude = 100 + x1 cos 30°
Departure = 200 + x1 sin 30°
Line QR
Latitude = 1000 – x2 cos 45°
Departure = 1000 – x2 sin 45°
For closed traverse, 100 + x1 cos 30° = 1000 – x2 cos 45°
⇒ x1 cos 30° + x2 cos 45° = 900 200 + x1 sin 30° = 1000 – x2 sin 45°
⇒ x1 sin 30° + x2 sin 45° = 800
∴ x1 = 273.205 m , x2 = 938.186 cm.
