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The following measurements were made during testing a levelling instrument.
P1 is close to P and Q1 is close to Q. If the reduced level of station P is 100.000 m, the reduced level of station Q is
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- 99.000 m
- 100.000 m
- 101.000 m
- 102.000 m
- 99.000 m
Correct Option: C
Apparant diff. in elevation (from P) = 1.700 – 2.800 = – 1.1 m
Apparant diff. in elevation (from Q) = 1.800 – 2.700 = – 0.90 m
| ∴ True difference = | = 1 m | |
| 2 |
∴ True elevation of Q = 100 + 1 = 101 m
