The chainage of the intersection point of two straights

The chainage of the intersection point of two straights is 1585.60 m and the angle of intersection is 140°. If the radius of a circular curve is 600.00 m, the tangent distance (in m) and length of the curve (in m). respectively are

1. 418.88 and 1466.08
2. 218.38 and 1648.49
3. 218.38 and 418.88
4. 418.88 and 218.38

∆ = 180° – 140° = 40°

Length of curve =	πR ∆
	180°

=	π × 600 × 40	= 418.82 m
	180

Tangent distance, T = OT₁ tan	∆	(OT₁ = radius = R)
	2

= 600 × tan	40	= 218.88 m
	2