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A file system with 300 Gbyte disk uses a file descriptor with 8 direct block addresses, 1 indirect block address and 1 doubly indirect block address. The size of each disk block is 128 byte and the size of each disk block address is 8 byte. The maximum possible file system is
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- 3 kbyte
- 35 kbyte
- 280 kbyte
- dependent on the size of the disk
- 3 kbyte
Correct Option: B
Total number of possible addresses stored in a disk block = 128/8 = 16
Maximum number of addressable bytes due to direct address block = 8 × 128
Maximum number of addressable bytes due to 1 single indirect address block = 16 × 128
Maximum number of addressable bytes due to 1 double indirect address block = 16 × 16 × 128
The maximum possible file size = 8 × 128 + 16 × 128 + 16 × 16 × 128 = 35 Kbyte
