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Given digits 2, 2, 3, 3, 3, 4, 4, 4, 4 how many distinct 4 digit numbers greater than 3000 can be formed?
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- 50
- 51
- 52
- 54
- 50
Correct Option: B
Case 1: First Digit = 3 ⇒ 3...
Rest 3 digits may be combination of
234 → 3!
| 223 → | |
| 2! |
| 224 → | |
| 2! |
| 332 → | |
| 2! |
| 334 → | |
| 2! |
| 442 → | |
| 2! |
| 443 → | |
| 2! |
444 → 1
∴ Total combinations = 25
Case 2: First Digit = 4 ⇒ 4...
Rest 3 digits may be combination of
234 → 6
223 → 3
224 → 3
332 → 3
334 → 3
442 → 3
443 → 3
444 → 1
333 → 1
∴ Total combinations = 26
∴ Required answer = 25 + 26 = 51
