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A political party orders an arch for the entrance to the ground in which the annual conventions is being held. The profile of the arch follows the equation y = 2x – 0.1x2 where y is the height of the arch in meters. The maximum possible height of the arch is
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- 8 meters
- 10 meters
- 12 meters
- 14 meters
- 8 meters
Correct Option: B
y = 2x – 0.1x2
= 2 – 0.2x | ||
dx |
< 0 | ||
dx2 |
Hence maximises at 2 – 0.2x = 0
⇒ x = 10
∴ y = 20 – 10 = 10 m