What will be the maximum sum of 44, 42, 40, ........, 2,

S_n =	n	[ 2a + (n - 1)d ]
	2

44, 42, 40, ------ 2, 0
Here , a = 44 , d = -2 , n = 22 terms

S₂₂ =	22	[ 2 × 44 + (22 - 1)(-2) ]
	2

S₂₂ =	22	[ 88 - 42 ]
	2

S₂₂ =	22	× [ 46 ]
	2

S₂₂ = 11 × 46 = 506