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A car is moving at a speed of 72 km/hr on road having 2% upward gradient. The driver applies brakes when he sees an obstruction. If his reaciton time is 1.5 seconds, assuming that the co-efficient of friction between the pavement and tyre as 0.15, calculate the distance traversed before the car finally stops.
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- 24 m
- 150 m
- 1056 m
- 324 m
- 24 m
Correct Option: B
| SSD = vt + | (v in m / s) | |
| 2g(f + 0.01n) |
| = 0.278 vt + | ||
| 254(f + 0.01n) |
| = 0.278 × 72 × 1.5 + | = 150 m | |
| 254(0.15 + 2 × 0.01) |
