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Velocity distribution in a boundary layer flow over a plate is given by (u/um) = 1.5η where, η = y / δ ; y is the distance measured normal to the plate; δ is the is the boundary layer thickness; and um is the maximum velocity at y = δ. If the shear stress t, acting on the plate is given by
τ = K( μum )/ δ
where, μ is the dynamic viscosity of the fluid, K takes the value of
-
- 0
- 1
- 1.5
- none of the above
Correct Option: C
| = 1.5 η = 1.5 × | |||
| um | δ |
| ∴ u = 1.5 × |  |  | × um | |
| δ |
| = | |||
| dy | δ |
| τ = μ | ||
| δ |
| = 1.5 | ||
| δ |
| τ = k | ||
| δ |
∴ k = 1.5
