Cross-section of an object (having same section normal to

Cross-section of an object (having same section normal to the paper) submerged into a fluid consists of a square of sides 2 m and triangle as shown in the figure. The object is hinged at point P that is one meter below the fluid free surface. If the object is to be kept in the position as shown in the figure, the value ‘x’ should be

Take moment of vertical component of hydrastatic force on two section

V₁0 +	2	= V₂ ×	x
	2		3

ρ _gv₁ × 1	= ρ_gv₂ ×	x
		3

∴ v₁ =	= v₂	x
		3

(2 × z × w) =		1	x × 2		(w) ×	x
		2				3

⇒ x = √12 = 2√3