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A circular sewer 2m diameter has to carry a discharge of 2m³ /s when flowing nearly full. What is the minimum required slope to initiate the flow? Assume Manning’s N = 0.015.
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- 0.00023
- 0.000036
- 0.000091
- 0.000014
Correct Option: A
Manning’s equation
| V = | m2/3C.1/2 | |
| n |
| ⇒ | = | m2/3C.1/2 | ||
| A | n |
| m = R = | = | m2/3C.1/2 | ||
| P | πD |
| = | |
| 2 |
| = | |
| 2 |
N = 0.015
G = 2 m³ /s
| A = | × 2² = π | |
| 4 |
| ⇒ | = | − | ![]() | ![]() | 2/3 | (i)1/2 | |||
| π | 0.015 | 2 |
∴ i = 0.00023

