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The top width and the depth of flow in a triangular channel were measured as 4 m and 1 m, respectively. The measured velocities on the centre line at the water surface, 0.2 m and 0.8 m below the surface are 0.7 m/s, 0.6 m/s and 0.4 m/s, respectively. Using two-point method of velocity measurement, the discharge (in m³ /s) in the channel is
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- 1.4
- 1.2
- 1.0
- 0.8
Correct Option: C
Vavg = | |
2 |
= | = 0.5 m/s | |
2 |
A = | × T × y | |
2 |
A = | × 4 × 1 = 2 m² | |
2 |
Q = Av = 2 × 0.5 = 1 m³ /s.