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In a wastewater treatment plant, primary sedimentation tank (PST) designed at an overflow rate of 32.5 m³/day/m² is 32.5 m long, 8.0 m wide and liquid depth of 2.25 m. If the length of the weir is 75 m, the weir loading rate (in m³/day/m) is
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- 111.67 m³/d/m
- 110.67 m³/d/m
- 109.67 m³/d/m
- 112.67 m³/d/m
Correct Option: D
112.67
SOR = 32.5 m³/d/m²
L = 32.5 m
B = 8 m, D = 2.25 m
| SOR = | ||
| BL |
∴ Q = SOR × B.L
= 32.5 × 8 × 32.5
= 8450 m³/d
| q = | ||
| b |
b = 75 m (weir length)
| q = | ||
| 75 |
= 112.67 m³/d/m
