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A water treatment plant of capacity, 1 m³/s has filter boxes of dimensions 6 m × 10 m. Loading rate to the filters is 120 m³/day/m². When two of the filters are out of service for back washing, the loading rate (in m³/day/m²) is
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- 144 m³/d/m²
- 147 m³/d/m²
- 146 m³/d/m²
- 145 m³/d/m²
Correct Option: A
144
Total water filtered/ day = 1 × 3600 × 24 = 86400 m³/ day
Surface area of filter bed = | = 720 m² | |
120 |
Surface area of filter bed = | = 720 m² | |
120 |
Area of one filter = 6 × 10 = 60 m²
∴ No. of filter = | = 12 filters | |
60 |
filters are out of service, no. of filters = 12
∴ Total surface area of 10 filters = 10 × 60 = 600 m²
∴ Loading rate = 86400 600 = 144 m³/d/m²