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A direct shear test was conducted on a cohesion-less soil (c = 0) specimen under a normal stress of 200 kN/m2. The specimen failed at a shear stress of 100 kN/m2. The angle of internal friction of the soil (degrees) is
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- 26.6
- 29.5
- 30.0
- 32.6
Correct Option: B
τ = c + s tan Φ.
c = 0, τ = 100 kN/m2, σ= 200 kN/m2.
⇒ 100 = 200 tanΦ.
| ∴ tanΦ = | = | |||
| 200 | 2 |
∴ Φ = 26.56°
