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  1. A given cohesion less soil has emax = 0.85 and emin = 0.50. In the field, the soil is compacted to a mass density of 1800 kg/ m3 at a water content of 8%. Take the mass density of water as 1000 kg/m3 and Gs as 2.7. The relative density (in%) of the soil is
    1. 56.43
    2. 60.25
    3. 62.87
    4. 65.71
Correct Option: D

P =
Grw(1 + w)
1 + e

⇒ 1800 =
2.7 × 1000 × (1.08)
1 + e

∴ 1 + e =
2.7 × 1000 × 1.08
1800

∴ e = 0.02
ID =
emax - e
× 100
emax - emin

=
0.85 - 0.62
× 100
0.85 - 0.5

= 65.714%



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