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Stress path equation for tri-axial test upon application of deviatoric stress is, q = 10 √3 + 0.5 p. The respective values of cohesion, c (in kPa) and angle of internal friction, Φ are:
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- 20 and 20°
- 20 and 30°
- 30 and 30°
- 30 and 20°
Correct Option: B
Stress path equation
| = cosΦ + | sinΦ | |||
| 2 | 2 |
Given equation is
q = 10 √3 + 0.5 p
Comparing both equation
C × cosΦ = 10√3
sin Φ = 0.5
⇒ Φ = sin–1 0.5 = 30°
∴ C × cos30° = 10√3
⇒ C = 20
