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An agricultural land of 437 ha is to be irrigated for a particular crop. The base period of the crop is 90 days and the total depth of water required by the crop is 105 cm. If a rainfall of 15 cm occurs during the base period, the duty of irrigation water is
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- 437 ha/cumec
- 486 ha/cumec
- 741 ha/cumec
- 864 ha/cumec
Correct Option: D
Net water required = 105 – 15 = 90 cm
D × Delta = Duty × Base period
D = | × 104 (m² to hectare) = 864 hectares/curve | |
0.9 |
Duty = | = | = 864 ha/cumec | ||
Δ | 90 |