Wheat crop requires 55 cm of water during 120 days of base

Wheat crop requires 55 cm of water during 120 days of base period. The total rainfall during this period is 100 mm. Assume the irrigation efficiency to be 60%. The area (in ha) of the land which can be irrigated with a canal flow of 0.01 m³/s is

Actual water depth required (D₁) = 55 – total rainfall
= 55 – 10 = 45 cm

D₁ =	864 × B
	D

⇒ 45 =	864 × 120
	D

D = 2304 ha/cumec
1 m³/s discharge → 2304 hectares (irrigation)
∴ 0.01 m³/s discharge → 2304 × 0.01 = 23.04 hectares

Actual irrigated area = 23.04 ×	60	= 13.824 hectares.
	100