Direction: An upward flow of oil (mass density 800 kg/m³, dynamic viscosity 0.8 kg/m–s) takes place under laminar conditions in an inclined pipe of 0.1 m diameter as shown in the figure. The pressures at section 1 and 2 are measured p1 = 435 kN/m² and p² = 200 kN/m².
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If the flow is reversed, keeping the same discharge, and the pressure at section 1 is maintained as 435 kN/m², the pressure at section 2 is equal to
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- 488 kN/m²
- 549 kN/m²
- 586 kN/m²
- 614 kN/m²
Correct Option: D
+ sin 45° = | + | |||
r | r | PgD² |
P2 = | ![]() | + | - | ![]() | × 800 × 9.81 = 614.48kN/m² | |||
800 × 9.81 | 800 × 9.81 × (0.1)² | V2 |
= 614.48 kN/m².