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A rigid link PQ is 2 m long and oriented at 20° to the horizontal as shown in the figure. The magnitude and direction of velocity VQ, and the direction of velocity VP are given. The magnitude of VP (in m/s) at this instant is
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- 2.14
- 1.89
- 1.21
- 0.96
- 2.14
Correct Option: D
By Instantaneous center method;say ω = angular velocity of rod
vq = rq . ω ...(i)
vp = rp . ω ...(ii) Dividing equation (i) with equation (ii) we get
= | ; vp = | .vq | ||||
vp | rp | rq |
Now by sine law, | = | |||
sin(45° + 20°) | sin(70°) |
= | ||||
rq | sin(70°) |
So , vp = | vq = 0.96 | |
sin(70°) |