In the mechanism given below, if the angular velocity of

In the mechanism given below, if the angular velocity of the eccentric circular disc is 1 rad/s, the angular velocity (rad/s) of the follower link for the instant shown in the figure is
[Note: All dimensions are in mm.]

∆PQR ∼ ∆SRO

∴	PQ	=	PO	.....(1)
	SR		SO

(PO)² = (PQ)² + (OQ)²
∴ PQ = √(PO)² - (OQ)²
= √50² - 25² = 43.3 mm
From (1),

	43.3	=	45 + 5
	SR		5

SR = 4.33 mm
V_Q = V_R = SR × ω
= 4.33 × 1 = 4.33 m/s

ω_PQ =	V_PQ	=	4.33	= 0.1 rad / sec
	PQ		43.3