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A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm thickness. The punch and the dia clearance is 3%. The required punch diameter is
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- 19.88 mm
- 19.94 mm
- 20.06 mm
- 20.12 mm
- 19.88 mm
Correct Option: A
Punch diameter = 20 – 2 × 3% of thickness
| Punch diameter = 20 – 2 × | × 2 = 20 - 0.12 = 19.88 mm | |
| 100 |
| Thickness of blank = | = 3 mm | |
| cos60° |
