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Minimum shear-strain in orthogonal turning with a cutting tool of zero rake angle is
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- 0.0
- 0.5
- 1.0
- 2.0
- 0.0
Correct Option: D
| Shear strain , τ = | ||
| sinφ.cos( φ - α ) |
where, α = 0 = rake angle , φ = shear angle
| ∴ τ = | ||
| sinθcosθ |
∴ T = sinφcosφ
| = cos ²φ - sin ²φ | ||
| dφ |
or φ = 45°
| ∴ τmin = | ||
| { sin (π /4).cos(π /4) } |
| ∴ τmin = | = 2 | |
| { sin (1 /√2) × (1 /√2) } |