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A steel bar 200 mm in a diameter is turned at a feed of 0.25 mm/rev. with a depth of cut of 4 mm. The rotational speed of the workpiece is 160 rpm. The material removal rate in mm3 / s is
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- 160
- 167.6
- 1600
- 1675.5
- 160
Correct Option: D
Material removal rate (MRR) in mm3/s MRR = f.d × V
MRR = 0.25 × 4 × | = 1675.5 mm3/s | |
60 |