-
Tool life of a 10 hours is obtained when cutting with a single point tool at 63 m/min. If Taylor's constant C = 257.35, tool life on doubling the velocity will be
-
- 5 hours
- 25.7 min
- 38.3 min
- unchanged
Correct Option: B
V1 =63m/min T1 = 60 hours = 600 min
C = 257.35
V1T1n = C
63 × (100)n = 257.35
n = 0.22
V2T2n = 257.35
2 V2T2n = 257.35
2 × 63 (T2)0.22= 257.35
T2 = 25.6min