In a CAD package, a point P(6,3,2) is projected along a

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In a CAD package, a point P(6,3,2) is projected along a vector V^rarr; (-2,1,-1). The projection of this point on X-Y plane will be

1. (4, 4, 0)
2. (8, 2, 0)
3. (7, 4, 0)
4. (2, 5, 0)

Correct Option: D

Let X (x, y, o) be the projection of point p (6, 3, 2) The unit vector of line joining point P and X should be same as Vˆ

where D = √(6 − x)² + (3 − y)² + 2²
on equating, Px and V, we get

6 − x	, =	−2	,	3 − y	=	1	,	2	=	−1
D	, =	√6	,	D	=	√6	,	D	=	√6

So D = −2√6

j = 3 −	(−2√6)	= 5
	√6

x = 6 −	(−2 × −2√6)	= 2.
	√6

z = 0