Direction: A reinforced concrete beam of rectangular cross section of breadth 230 mm and effective depth 400 mm is subjected to a maximum factored shear force of 120 kN. The grade of concrete, mains steel and stirrup steel are M20, F415 and Fe250 respectively. For the area of main steel provided, the design shear strength τc as per IS : 456-2000 is 0.48 N/mm2. The beam is designed for collapse limit state.
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The spacing (mm) of 2-legged 8 mm stirrups to be provided is
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- 40
- 115
- 250
- 400
Correct Option: B
Total shear force = 0.48 × 230 × 400 =
44.16 kN (< 120kN)
∴ Net shear force, Vus = 120 – 44.16 = 75.84 kN
If ‘s’ is the spacing of sheer reinforcement
| Vs = | × 0.87 × fy × Ast | xs |
| Ast = 2 × | × 82 = 100.53 mm2 | 4 |
| ∴ s = | Vus |
| = | = 115.323 mm | 75.84 × 103 |
