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The maximum shear stress in a solid shaft of circular cross-section having diameter subjected to a torque T is t. If the torque is increased by four times and the diameter of the shaft is increased by two times, the maximum shear stress in the shaft will be
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- 2t
- t
- t/2
- t/4
Correct Option: C
= | ||||
r | J |
τ1 | J = | d4 | ||
J | 32 |
= | ||
d4 | ||
32 |
τ2 = | ||
(2d)4 | ||
32 |
= | ||
16d4 | ||
32 |
∴ | = | |||
τ1 | 2 |
∴ τ2 = | 2 |