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If the following equation establishes equilibrium in slightly bent position, the mid-span deflection of a member shown in the figure is
d2y + P y = 0 dx2 EI 
If a is amplitude constant for y, then
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y = 1 
1 - a cos 2πx 
P L -
y = 1 1 - a sin 2πx P L -
y = a sin nπx L -
y = a cos nπx L
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Correct Option: C
| = | .y = - m2y | |||
| dx2 | EI |
Solution of above equation is:
y = a sin mx + b cos nx
at x = 0, y = 0
0 = a × 0 + b × 1
∴ b = 0
at x = L, y = 0
0 = a sin mL
∴ mL = nπ
| ∴ m = | L |
| y = a sin | L |
