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Mathematical idealization of a crane has three bars with their vertices arranged as shown in the figure with a load of 80 kN hanging vertically. The coordinates of the vertices are given in the parentheses. The force in the member QR, FQR will be
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- 30 kN Compressive
- 30 kN Tensile
- 50 kN Compressive
- 50 kN Tensile
Correct Option: A
Take moment about R
∑ MR = 0
80 × 3 = VQ × 2
∴ Va = 120 kN
Consider Joint Q
∠ PQR = 104.03°
∴ Q = 104.03° – 90 = 14.03°
Resolve vertically,
∑ Fv = 0
FQP .cos + VQ = 0
∴ FQP = | cos14.03° |
Resolve horizontally,
∑ FH = 0
FQP sin θ = FQR
× sin14.03° = FQR | cos14.03° |
∴ FQR = 120 × tan 14.03° = 30 kNM