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The input link O2P of a four bar linkage is rotated at 2 rad/s in counter clockwise direction as shown below. The angular velocity of the coupler PQ in rad/s, at an instant when ∠O4O2P = 180°, is
PQ = Q4Q = √2a
O2P = O2O4 = a
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- 4
- 2√2
- 1
- 1√2
Correct Option: C
When ∠O4O2 P = 180°
Now, | = | = | ||||
ω2 | I12I23 | 2a |
= | ||||
2 | 2 |
ω3 = 1 rad/s