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In the figure shown, the relative velocity of link 1 with respect of link 2 is 12 m/s. Link 2 rotates at a constant speed of 120 rpm. The magnitude of Coriolis component of acceleration of link 1 is
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- 302 m/s2
- 906 m/s2
- 604 m/s2
- 1208 m/s2
Correct Option: A
Velocity of link 1 with respect to link 2,
V½ = 12 m/sω = = = 4π 60 60
∴ Corioli’s component of acceleration
= 2V½ω = 2 × 12 × 4π
= 301.59 ≈ 302 m/s2