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An epicyclic gear train is shown schematically in the adjacent figure. The sun gear 2 on the input shaft is a 20 teeth external gear. The planet gear 3 is a 40 teeth external gear. The ring gear 5 is a 100 teeth internal gear. The ring gear 5 is fixed and the gear 2 is rotating at 60 rpm ccw(ccw-counterclockwise and cw- clockwise)
The arm 4 attached to the output shaft will rotate at
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- 10 rpm ccw
- 10 rpm cw
- 12 rpm cw
- 12 rpm ccw
Correct Option: B
T2 = 20; T3 = 40; T5 =100
Given y –x | = 0 | T5 |
⇒ x = 5y ....(1)
and y + x = 60 ....(2)
Solving (1) and (2), we get
y + 5y = 60
⇒ y = 10 rpm ccw