Direction: A uniform rigid slender bar of mass 10 kg, hinged at the left end is suspended with the help of spring and damper arrangement as shown in the figure where K= 2 kN/m, C = 500 Ns/m and the stiffness of the torsional spring kθ is 1 kN /m/rad. Ignore the hinge dimensions.
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The damping coefficient in the vibration equation is given by
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- 500 Nms/rad
- 500 N/(m/s)
- 80 Nms/rad
- 80 N/(m/s)
Correct Option: C
For static equilibrium kt . θs + kt . Theta;s L2 = mgl2
For additional deflection θ, equation will be.
where, I = ml2/3
∴ Un-damped frequency,
= 42.426
= 42.43 rad/sec.
and, Equivalent damping coefficient
= Cl12 Nm/rad
= 500 × (0.04)2 = 80 Nms/rad