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A mass m attached to a spring is subjected to a harmonic force as shown in figure. The amplitude of the forced motion is observed to be 50 mm. The value of m (in kg) is
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- 0.1
- 1.0
- 0.3
- 0.5
Correct Option: A
Given: Amplitude of force motion, A = 50 mm
∴ F(t) = 100 cos (100t) ...(i)
ω = 100
General solution is, x = A cos ωt
Putting in equation (i), we have
m (- Aω2 cosωt) + K (A cosωt) = 100 cos (ωt)
⇒ – mω2A + kA = 100
Here k = 3000 N/m
∴ – m (0.05) (100)2 + 3000 (0.05) = 100
m = | = 0.1 | 100 |