-
A closed cylinder having a radius R and height H is filled with oil of density ρ. If the cylinder is rotated about its axis at an angular velocity of ω, the thrust at the bottom of the cylinder is
-
- πR2ρ.gH
-
πR2 ρ ω2 R2 4 - πR2(ρ ω2R2 + ρ gH)
-
πR2 ρ ω2R2 + ρ gH 4
Correct Option: D
We know that
= | = | = δω2r | ||||
δr | r | r |
[∵ v = ω × r]
p | δp = | r | ρω2r dr | 0 | 0 |
p = | ω2r2 | 2 |
Area of circular ring = 2πrdr
Force on elementry ring
= Intensity of pressure × Area of ring
= | ω2r22πr dr | 2 |
∴ Total force on the top of the cylinder
= | R | ρω2r22π r dr | 0 | 2 |
= | ρω2r22π | R | r3 dr | 2 | 0 |
. ω22π | = | ω2 × πR4 | ||||
2 | 4 | 4 |
Thrust at the bottom of the cylinder
= Weight of water in cylinder + Total force on the top of cylinder
= ρg × πR2 × H + | ω2 × πR4 | 4 |
= πR2 | + ρgH | ||||
4 |