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In a Lagrangian system, the position of a fluid particle in a flow is described as x = x0e–kt and y = y0ekt where t is the time while x0, y0, and k are constants. The flow is
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- unsteady and one-dimensional
- steady and two-dimensional
- steady and one-dimensional
- unsteady and two-dimensional
Correct Option: B
x direction scalar of velocity field,
| u = | dt |
u = - kx0e-kt
y direction scalar of velocity field
| v = | dt |
v = ky0ekt
v̄ = uî + vĵ
V̄ = - kx0e-ktî + ky0ektĵ
u & v are non zero scalar t ≥ 0 so it is 2D flow. 2D possible flow field
| + | = 0 | |||
| δx | δy |
| (- kx0e-kt) + | (ky0ekt) = 0 | |||
| δx | δy |
0 + 0 = 0 continuity satisfied.
| + k2x0e-kt | δt |
| + k2y0ekt | δt |
| ≠ 0 | δt |
| ≠ 0 | δt |
So, flow is unsteady.