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Fluid Mechanics and Hydraulic Machinery Miscellaneous

Fluid Mechanics and Hydraulic Machinery

  1. In a Lagrangian system, the position of a fluid particle in a flow is described as x = x0e–kt and y = y0ekt where t is the time while x0, y0, and k are constants. The flow is
    1. unsteady and one-dimensional
    2. steady and two-dimensional
    3. steady and one-dimensional
    4. unsteady and two-dimensional
Correct Option: B

x direction scalar of velocity field,

u =
dx
dt

u = - kx0e-kt
y direction scalar of velocity field
v =
dy
dt

v = ky0ekt
v̄ = uî + vĵ
V̄ = - kx0e-ktî + ky0ekt
u & v are non zero scalar t ≥ 0 so it is 2D flow. 2D possible flow field
δu
+
δv
= 0
δxδy

δ
(- kx0e-kt) +
δ
(ky0ekt) = 0
δxδy

0 + 0 = 0 continuity satisfied.
δu
+ k2x0e-kt
δt

δv
+ k2y0ekt
δt

δu
≠ 0
δt

δv
≠ 0
δt

So, flow is unsteady.



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