Home » Fluid Mechanics and Hydraulic Machinery » Fluid Mechanics and Hydraulic Machinery Miscellaneous » Question

Fluid Mechanics and Hydraulic Machinery Miscellaneous

Fluid Mechanics and Hydraulic Machinery

  1. Air flows through a venturi and into atmosphere. Air density is ρa; atmospheric pressure is ρa; throat diameter is Dt; exit diameter is D and exit velocity is U. The throat is connected to a cylinder containing a friction less piston attached to a spring. The spring constant is k. The bottom surface of the piston is exposed to atmosphere. Due to the flow, the piston moves by distance x. Assuming in compressible friction less flow, x is
    1. (ρU2/2k)πD2s
    2. (ρU2/8k)
      D2
      - 1πD2s
      D2t
    3. (ρU2/2k)
      D2
      - 1πD2s
      D2t
    4. (ρU2/8k)
      D4
      - 1πD2s
      D4t
Correct Option: D


Applying Bernoulli’s equation at points (1) and (2), we have

p1
+
v21
+ z1 =
p2
+
p22
+ z2
ρg2gρg2g

Since venturi is horizontal
z1 = z2
Now
p1
-
p2
=
v22
-
p21
ρgρg2g2g

⇒(p1 - p2) =
ρg
(v22 - v21) =
ρ
= (v22 - v21)
2gg

Since P2 = Pa = atmospheric pressure
∴ (P2 - Pa)
ρ
(v22 - v21) ........(i)
2

Applying continuity equation at points (i) and (ii), we have
A1 v1 = A2 v2
⇒ v1 =
A2
v2 since V2 = U
A1


v1 =
D
2U
Dt

From equation (i),

At point P
Spring force = pressure force due air



Your comments will be displayed only after manual approval.