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A siphon draws water from a reservoir and discharge it out at atmospheric pressure.
Assuming ideal fluid and the reservoir is large, the velocity at point Pin the siphon tube is
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- √2gh1
- √2g h2
- √2g(h2 - h1 )
- √2g(h2 + h1)
Correct Option: B
By energy conservation, velocity at point
Q = √2g(h2 - h1)
As there is a continuous and uniform flow, so velocity of liquid at point Q and P is same. 
Vp =√2g(h2 - h1)
