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By application of tensile force, the cross sectional area of bar P is first reduced by 30% and then by an additional 20%. Another bar Q of the same material is reduced in cross sectional area by 50% in a single step by applying tensile force. After deformation, the true strain in bar P and bar Q will, respectively be
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- 0.5 and 0.5
- 0.58 and 0.69
- 0.69 and 0.69
- 0.78 and 1.00
Correct Option: B
True strain
| ε = In |  |  | Af |
| εT = In | | | 0.8 × 0.7Ai |
| εT = In | | | 0.56 |
εT = 0.58
True strain in single step of 50%
| εT = In | | | Af |
| = In | | | 0.5Ai |
εT = In(2) = 0.693
