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The Newtonian fluid has the following velocity field:
= x²yî + 2xy²ĵ - yz³k̂
The rate shear deformation εyz at the point x = –2, y = –1 and z = 2 for the given flow is
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- –6
- –2
- –12
- 4
Correct Option: A
V = x⊃î + 2xy²zĵ - yz²̂k
Shear strain
yz = | + | = | (2xy² - z³) | ||||||
2 | δz | δy | 2 |
at (–2π, 2), we get
yz = | (- 4 - 8)) = - 6 | |
2 |