Direction: An orthogonal operation is carried out at 20 m/min cutting speed, using a cutting tool of rake angle 15 degree. The chip thickness is 0.4 mm and uncut chip thickness is 0.2 mm.
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The shear angle (in degrees) is
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- 26.8
- 27.8
- 28.8
- 29.8
Correct Option: C
V = 20m/min ∝ 15° t2 = 0.4 mm t1 = 0.2 mm r cos tan 1 rsin 0.2 cos15 0.4 tan 0.2 1 sin15 0.4
| tanφ = | ||
| 1 - rsin∝ |
| tanφ = | + cos 15 | ||
| 0.4 | |||
| 1 - | sin 15 | ||
| 0.4 | |||
φ = 29°
