Direction: During orthogonal machining of a mild steel specimen with a cutting tool of zero rake angle, the following data is obtained: Uncut chip thickness = 0.25 mm Chip thickness = 0.75 mm Normal force = 950 N Thrust force = 475 N
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The ultimate shear stress (in N/mm²) of the work material is
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- 235
- 139
- 564
- 380
Correct Option: D
| τs = | sinφ | |
| Wt1 |
| = | sin 18.43° | |
| 2.5 × 0.25 |
τ = 380N/mm²
